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Thursday, September 1, 2016

Plans for September 1

I am really sorry for being out, but a fever and stomach issues are forcing me to go back home. Please do the following for today:

Periods 1-2, 8-9
The quizzam is still on for tomorrow, so today be sure to get into study groups and be sure the various homework sets are making sense. Homework sets are collected tomorrow. Be sure the lab is shared with me at You can try the practice problems the substitute teacher will pass out, and these and solutions are on my school site: go to the 3 Chem-Phys site and in the Foundations folder is the file called Review Set. Other resources include reviewing sections in the textbook, trying other odd problems and checking answers in the back, and trying and checking yourself with the worked examples in every section. We are doing stuff from chapters 1 and 2 primarily.

Quizzam main topics: 
Vector addition, subtraction                 Vector multiplication
Derivatives of functions (no algebra required!), y = cxn
1-D motion problems with constant acceleration and non-constant acceleration
2-D motion: relative motion, projectiles
Motion graphs        Graphing data           Standard deviation, error bars

Period 3
We will hold off on your rankings of issues until tomorrow. Today, I want you to try getting data for our speed lab. You will get the lab sheet and some additional direction from the substitute teacher. The measurements you will need to make are for a marble rolling down a ramp and onto the table-top. You will need to select 5 different distances from the end of the ramp, and then for each distance do 4 time trials; you will be using the average time for each distance you select. Be sure to start the marble at the same height on the ramp every time you let it go, because you want to have the same speed on the table every single time. Keep track of all this with a data table you and your partners decide on. Ultimately we will be making a graph to determine the speed of the marble. Remember that speed = (distance)/(time), or v = d/t. We will get into the analysis tomorrow.

Thank you everyone, and let's make the most of it until tomorrow. Happy Thursday!    :-)

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